# Statistics Assignment | Professional Writing Services |

# This is an individual assignment in which cooperation is not permitted. # Reference all sources. # For the Pearson linear correlation test as shown below, # describe the assumptions and purpose of the test.## Explain the meaning of the following output items:# 1) statistic t,# 2) degrees of freedom f,# 3) p-value,# 4) alternate hypothesis,# 5) 95% confidence interval,

# 6) sample estimate.## Can one reject at 0.05 level of significance # null hypothesis of zero correlation of x, y?x <- 1:20true.y <- 2*x + 5amt.noise <- 30y <- true.y + amt.noise*rnorm(length(x))cor.test(x,y)# Pearson’s product-moment correlation# # data: x and y# t = -0.455, df = 18, p-value = 0.65# alternative hypothesis: true correlation is not equal to 0# 95 percent confidence interval:# -0.52434 0.35260# sample estimates:# cor # -0.10655
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## Statistics Assignment | Professional Writing Services |

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# Statistics Assignment | Professional Writing Services |

# This is an individual assignment in which cooperation is not permitted. # Reference all sources. # For the Pearson linear correlation test as shown below, # describe the assumptions and purpose of the test.## Explain the meaning of the following output items:# 1) statistic t,# 2) degrees of freedom f,# 3) p-value,# 4) alternate hypothesis,# 5) 95% confidence interval,

# 6) sample estimate.## Can one reject at 0.05 level of significance # null hypothesis of zero correlation of x, y?x <- 1:20true.y <- 2*x + 5amt.noise <- 30y <- true.y + amt.noise*rnorm(length(x))cor.test(x,y)# Pearson’s product-moment correlation# # data: x and y# t = -0.455, df = 18, p-value = 0.65# alternative hypothesis: true correlation is not equal to 0# 95 percent confidence interval:# -0.52434 0.35260# sample estimates:# cor # -0.10655
Get Statistics homework help today