Hypothesis Assignment | Professional Writing Services

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Hypothesis Assignment | Professional Writing Services

i need someone to check my response to my scenario. someone said this is slightly incorrect. im not sure if that is true.
The hypothesis scenario:
A doctor wants to know if the median BMI of a group of 100 patients with presumed overweight is equal to 30. (this is the medical value to know if you are overweight) Given the sample mean of 31.

Based on historical data, the doctor knows that these patients have a standard deviation of 5, so he uses this value as the standard deviation of the population in a Z test of 1 sample.
My response:
Null hypothesis H0: μ =30
Alternative Hypothesis H1; μ >30
You can put this in calculator
z0​=5/100​ √31−30​=2
=1-Norm.dist(2,0,1 true) ???
=0.02275
=Norm.s.inv ____?
Using the Z to P value calculator with α =0.05 and z=2, you get 0.9772
P value= 1−0.9772=0.0228
Mo : le = 30H, : M 7 3 D7 = 31T = 5n = 100Z = Z-l31-305= 2p – value = P(z xz )= P ( Z72 )I excel function= 1 – NounDist ( 2, 0, 1, truel ) )= 0 . 02275d = 0.05Sinceprvalue is less…
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Hypothesis Assignment | Professional Writing Services

 

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Hypothesis Assignment | Professional Writing Services

i need someone to check my response to my scenario. someone said this is slightly incorrect. im not sure if that is true.
The hypothesis scenario:
A doctor wants to know if the median BMI of a group of 100 patients with presumed overweight is equal to 30. (this is the medical value to know if you are overweight) Given the sample mean of 31.

Based on historical data, the doctor knows that these patients have a standard deviation of 5, so he uses this value as the standard deviation of the population in a Z test of 1 sample.
My response:
Null hypothesis H0: μ =30
Alternative Hypothesis H1; μ >30
You can put this in calculator
z0​=5/100​ √31−30​=2
=1-Norm.dist(2,0,1 true) ???
=0.02275
=Norm.s.inv ____?
Using the Z to P value calculator with α =0.05 and z=2, you get 0.9772
P value= 1−0.9772=0.0228
Mo : le = 30H, : M 7 3 D7 = 31T = 5n = 100Z = Z-l31-305= 2p – value = P(z xz )= P ( Z72 )I excel function= 1 – NounDist ( 2, 0, 1, truel ) )= 0 . 02275d = 0.05Sinceprvalue is less…
Get Statistics homework help today
TOP ACADEMIC WRITER
He has decades of experience in the education field and has served in the examination boards of some of the top Universities within & outside the United States America.

Hypothesis Assignment | Professional Writing Services